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a(n)=16*n!/(253*43!).
0

%I #2 Mar 30 2012 17:34:34

%S 5760,270720,12994560,636733440,31836672000,1623670272000,

%T 84430854144000,4474835269632000,241641104560128000,

%U 13290260750807040000,744254602045194240000,42422512316576071680000

%N a(n)=16*n!/(253*43!).

%F a(n)=48*(19!/24!)*(8!/3!)*n!/(43!)

%t Flatten[Table[If[IntegerQ[48*(19!/24!)*(8!/3!)*n!/(43!)], 48*(19!/24!)*(8!/ 3!)*n!/(43!), {}], {n, 0, 48 + 24}]]

%K nonn,less

%O 46,1

%A _Roger L. Bagula_, Mar 10 2009

%E Edited by the Associate Editors of the OEIS, May 27 2009