OFFSET
1,1
COMMENTS
The identity (781250*n^2 - 1107500*n + 392499)^2 - (625*n^2 - 886*n + 314)*(31250*n - 22150)^2 = 1 can be written as A157620(n)^2 - a(n)*A157619(n)^2 = 1.
The continued fraction expansion of sqrt(a(n)) is [25n-18; {3, 1, 1, 3, 50n-36}]. - Magus K. Chu, Sep 30 2022
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
Vincenzo Librandi, X^2-AY^2=1
Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
FORMULA
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3).
G.f.: x*(-53 - 883*x - 314*x^2)/(x-1)^3.
MATHEMATICA
Table[625n^2-886n+314, {n, 40}] (* Harvey P. Dale, Jan 29 2011 *)
PROG
(Magma) I:=[53, 1042, 3281]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]];
(PARI) a(n) = 625*n^2 - 886*n + 314.
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 03 2009
STATUS
approved