|
|
A157443
|
|
a(n) = 121*n^2 - 38*n + 3.
|
|
3
|
|
|
86, 411, 978, 1787, 2838, 4131, 5666, 7443, 9462, 11723, 14226, 16971, 19958, 23187, 26658, 30371, 34326, 38523, 42962, 47643, 52566, 57731, 63138, 68787, 74678, 80811, 87186, 93803, 100662, 107763, 115106, 122691, 130518, 138587, 146898
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
The identity (14641*n^2 - 4598*n + 362)^2 - (121*n^2 - 38*n + 3)*(1331*n - 209)^2 = 1 can be written as A157445(n)^2 - a(n)*A157444(n)^2 = 1. - Vincenzo Librandi, Jan 26 2012
The continued fraction expansion of sqrt(a(n)) is [11n-2; {3, 1, 1, 1, 11n-3, 1, 1, 1, 3, 22n-4}]. - Magus K. Chu, Sep 13 2022
|
|
LINKS
|
|
|
FORMULA
|
|
|
MATHEMATICA
|
LinearRecurrence[{3, -3, 1}, {86, 411, 978}, 40] (* Vincenzo Librandi, Jan 26 2012 *)
|
|
PROG
|
(Magma) I:=[86, 411, 978]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]]; // Vincenzo Librandi, Jan 26 2012
(PARI) for(n=1, 22, print1(121*n^2 - 38*n + 3", ")); \\ Vincenzo Librandi, Jan 26 2012
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|