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A156826
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Square array read by anti diagonals up.
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1
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1, 2, -1, 3, 1, -1, 4, -1, 0, -1, 5, 2, 1, 0, -1, 6, -2, -1, 0, 0, -1, 7, 3, -1, 1, 0, 0, -1, 8, -3, 2, -1, 0, 0, 0, -1, 9, 4, -2, -1, 1, 0, 0, 0, -1, 10, -4, -2, -1, -1, 0, 0, 0, 0, -1, 11, 5, 3, 2, -1, 1, 0, 0, 0, 0, -1, 12, -5, -3, -2, -1, -1, 0, 0, 0, 0, 0, -1, 13, 6, -3, -2, -1, -1, 1, 0, 0
(list; table; graph; refs; listen; history; internal format)
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OFFSET
| 1,2
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COMMENTS
| This square array is the same as A126988 except that the first row is A153881.
Replace the zeros with -n/k. That is, the fraction of the row index divided by the column index with a negative sign. Then swap the element in the lower right corner with the element in the upper right corner and calculate the determinant. The result appears to be sequence A156827.
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EXAMPLE
| Table begins:
1.-1.-1.-1.-1.-1.-1.-1.-1.-1.-1.-1.-1
2..1..0..0..0..0..0..0..0..0..0..0..0
3..0..1..0..0..0..0..0..0..0..0..0..0
4..2..0..1..0..0..0..0..0..0..0..0..0
5..0..0..0..1..0..0..0..0..0..0..0..0
6..3..2..0..0..1..0..0..0..0..0..0..0
7..0..0..0..0..0..1..0..0..0..0..0..0
8..4..0..2..0..0..0..1..0..0..0..0..0
9..0..3..0..0..0..0..0..1..0..0..0..0
10.5..0..0..2..0..0..0..0..1..0..0..0
11.0..0..0..0..0..0..0..0..0..1..0..0
12.6..4..3..0..2..0..0..0..0..0..1..0
13.0..0..0..0..0..0..0..0..0..0..0..1
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PROG
| (Other) (Excel cell formula) =rounddown(if(mod(row(); column())=0; row()/column(); -row()/column())*if(row()=1; column(); 1); 0)
(Excel cell formula) with fractions: =if(mod(row(); column())=0; row()/column(); -row()/column())*if(row()=1; column(); 1)
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CROSSREFS
| Cf. A126988, A153881, A156827.
Sequence in context: A006346 A088742 A144220 * A130296 A126705 A113924
Adjacent sequences: A156823 A156824 A156825 * A156827 A156828 A156829
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KEYWORD
| sign,tabl
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AUTHOR
| Mats Granvik (mats.granvik(AT)abo.fi), Feb 16 2009
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