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a(n) = 17*((100^(n+1) - 1)/99).
1

%I #18 Sep 04 2024 18:54:50

%S 17,1717,171717,17171717,1717171717,171717171717,17171717171717,

%T 1717171717171717,171717171717171717,17171717171717171717,

%U 1717171717171717171717,171717171717171717171717

%N a(n) = 17*((100^(n+1) - 1)/99).

%H Vincenzo Librandi, <a href="/A156675/b156675.txt">Table of n, a(n) for n = 0..100</a>

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (101,-100).

%F G.f.: 17/(1 - 101*x + 100*x^2). - _Bruno Berselli_, Mar 01 2012

%o (Magma) [17*((100^(n+1)-1)/99): n in [0..20]]; // _Vincenzo Librandi_, Mar 01 2012

%Y Cf. A094028.

%K nonn,easy

%O 0,1

%A _Vincenzo Librandi_, Feb 15 2009

%E Offset changed to 0 from _Vincenzo Librandi_, Mar 01 2012