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a(n)=8*A154811(n).
0

%I #11 Dec 12 2023 08:03:52

%S 8,16,40,32,56,64,64,56,32,40,16,8,8,16,40,32,56,64,64,56,32,40,16,8,

%T 8,16,40,32,56,64,64,56,32,40,16,8,8,16,40,32,56,64,64,56,32,40,16,8,

%U 8,16,40,32,56,64,64,56,32,40,16,8,8,16,40,32,56,64,64,56,32,40,16,8,8,16,40

%N a(n)=8*A154811(n).

%H <a href="/index/Rec#order_07">Index entries for linear recurrences with constant coefficients</a>, signature (1, 0, 0, 0, 0, -1, 1).

%F Period length 12: a(n)=a(n-12).

%F a(n) = A154811(n+6) = A155110(n) (mod 9).

%t 8*Mod[Fibonacci[Range[1,151,2]],9] (* or *) PadRight[{},80,{8,16,40,32,56,64,64,56,32,40,16,8}] (* _Harvey P. Dale_, Jul 10 2018 *)

%K nonn,easy

%O 0,1

%A _Paul Curtz_, Feb 08 2009

%E Edited and extended by _R. J. Mathar_, Apr 10 2009