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A155918
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Number of squared hypotenuses mod n in two dimensions.
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6
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1, 2, 3, 3, 5, 6, 7, 5, 7, 10, 11, 9, 13, 14, 15, 9, 17, 14, 19, 15, 21, 22, 23, 15, 25, 26, 21, 21, 29, 30, 31, 17, 33, 34, 35, 21, 37, 38, 39, 25, 41, 42, 43, 33, 35, 46, 47, 27, 43, 50, 51, 39, 53, 42, 55, 35, 57, 58, 59, 45, 61, 62, 49, 33, 65, 66, 67, 51, 69, 70, 71, 35, 73
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OFFSET
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1,2
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COMMENTS
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Number of images of the map (x,y) -> x^2+y^2 in Z_n.
Let n = p^e and k = r*p^b (gcd(r,p) = 1). If p == 1 (mod 4), then x^2 + y^2 == k (mod p) always have solutions; if p == 3 (mod 4), then x^2 + y^2 == k (mod p) is solvable if and only if b is even or b >= e; if p = 2, then x^2 + y^2 == k (mod p) is solvable if and only if r == 1 (mod 4) or b >= e - 1. If 0 <= k < n, then the number of solutions to x^2 + y^2 == k (mod n) is A305191(n,k). - Jianing Song, Apr 20 2019
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LINKS
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FORMULA
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Multiplicative with a(p^e) = p^e if p == 1 (mod 4); ceiling(p^(e+1)/(p+1)) if p == 3 (mod 4); 2^(e-1) + 1 if p = 2. - Jianing Song, Apr 20 2019
Sum_{k=1..n} a(k) ~ c * n^2, where c = (11/24) * Product_{p prime == 3 (mod 4)} (1 - 1/p^3)/(1 - 1/p^4) = (11/24) * A334427/A334448 = 0.44532386516028771931... . - Amiram Eldar, Feb 17 2024
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MATHEMATICA
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(For[v = Table[0, {m, 1, n^2}]; m = 1; i = 0, i < n, i++, For[j = 0, j < n, j++, v[[m]] = Mod[i^2 + j^2, n]; m = m + 1]]; Length[Union[v]])
(* Second program: *)
a[n_] := Module[{p, e}, Product[{p, e} = pe; Which[Mod[p, 4] == 1, p^e, Mod[p, 4] == 3, Ceiling[p^(e+1)/(p+1)], p == 2, 2^(e-1) + 1, True, p], {pe, FactorInteger[n]}]];
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PROG
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(PARI) a(n) = #Set(vector(n^2, i, ((i%n)^2 + (i\n)^2) % n)); \\ Michel Marcus, Jul 08 2017
(PARI) a(n)=
{
my(r=1, f=factor(n));
for(j=1, #f[, 1], my(p=f[j, 1], e=f[j, 2]);
if(p==2, r*=2^(e-1)+1);
if(p%4==1, r*=p^e);
if(p%4==3, r*=ceil(p^(e+1)/(p+1)));
);
return(r);
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CROSSREFS
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KEYWORD
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mult,nonn
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AUTHOR
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STATUS
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approved
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