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Eleven times hexagonal numbers: 11*n*(2*n-1).
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%I #17 Jun 17 2017 04:38:08

%S 0,11,66,165,308,495,726,1001,1320,1683,2090,2541,3036,3575,4158,4785,

%T 5456,6171,6930,7733,8580,9471,10406,11385,12408,13475,14586,15741,

%U 16940,18183,19470,20801,22176,23595,25058,26565,28116,29711

%N Eleven times hexagonal numbers: 11*n*(2*n-1).

%C Sequence found by reading the line from 0, in the direction 0, 11,..., in the square spiral whose vertices are the generalized tridecagonal numbers A195313. - _Omar E. Pol_, Sep 18 2011

%H Ivan Panchenko, <a href="/A154617/b154617.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).

%F a(n) = 22*n^2 - 11*n = A000384(n)*11.

%F a(n) = a(n-1)+44*n-33 (With a(0)=0). - _Vincenzo Librandi_, Dec 15 2010

%o (PARI) a(n)=11*n*(2*n-1) \\ _Charles R Greathouse IV_, Jun 17 2017

%Y Cf. A000384, A002939, A094159, A152745, A153781.

%K easy,nonn

%O 0,2

%A _Omar E. Pol_, Jan 13 2009