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Greatest number m such that the fractional part of (4/3)^A154133(n) >= 1-(1/m).
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%I #5 May 10 2012 21:39:51

%S 1,4,88,1228,187,4562,8183,167378,35419,77421,5593723,3306511,

%T 83205705,22413581,24296709,35457806,26593355,19945016,80184972,

%U 389460601

%N Greatest number m such that the fractional part of (4/3)^A154133(n) >= 1-(1/m).

%F a(n):=floor(1/(1-fract((4/3)^A154133(n)))), where fract(x) = x-floor(x).

%e a(3)=88, since 1-(1/89)=0.988764...>fract((4/3)^A154133(3))=fract((4/3)^8)=0.988721...>0.988636...=1-(1/88).

%Y Cf. A153668, A153676, A153708, A153716, A154145, A154153.

%Y Cf. A002379, A064628.

%K nonn,more

%O 1,2

%A _Hieronymus Fischer_, Jan 11 2009

%E a(11)-a(20) from _Robert Price_, May 10 2012