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Greatest number m such that the fractional part of (4/3)^A154131(n) <= 1/m.
0

%I #6 Mar 03 2020 02:50:01

%S 3,6,30,6430,4822,22869,20551,224544,184762,2396968,15229280,3183837,

%T 2387878,28274047,7149842

%N Greatest number m such that the fractional part of (4/3)^A154131(n) <= 1/m.

%F a(n) = floor(1/fract((4/3)^A154131(n))), where fract(x) = x - floor(x).

%e a(3)=30 since 1/31<fract((4/3)^A154131(3))=fract((4/3)^17)=0.0327357...<=1/30.

%Y Cf. A153666, A153674, A153706, A153714, A154143, A154151.

%Y Cf. A002379, A064628.

%K nonn,more

%O 1,1

%A _Hieronymus Fischer_, Jan 11 2009

%E a(10)-a(15) from _Jinyuan Wang_, Mar 03 2020