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Greatest number m such that the fractional part of (10/9)^A153694(n) <= 1/m.
4

%I #6 Mar 03 2020 02:48:08

%S 9,4,11,82,6131,4549,26735,8620,14923,20328,151439,227416,771341,

%T 2712159,2676962,2409266,4490404,4041364

%N Greatest number m such that the fractional part of (10/9)^A153694(n) <= 1/m.

%F a(n) = floor(1/fract((10/9)^A153694(n))), where fract(x) = x - floor(x).

%e a(3) = 11 since 1/12 < fract((10/9)^A153694(3)) = fract((10/9)^7) = 0.09075... <= 1/11.

%Y Cf. A153662, A153670, A153678, A153686, A153694, A154130, A153706, A153714, A153722.

%K nonn,more

%O 1,1

%A _Hieronymus Fischer_, Jan 06 2009

%E a(14)-a(18) from _Jinyuan Wang_, Mar 03 2020