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A153216
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A triangular sequence of powers ( suppressed powers) : t(n,m)=m^Sum[Floor[n/m^k], {k, 1, Infinity}].
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0
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2, 2, 3, 8, 3, 4, 8, 3, 4, 5, 16, 9, 4, 5, 6, 16, 9, 4, 5, 6, 7, 128, 9, 16, 5, 6, 7, 8, 128, 81, 16, 5, 6, 7, 8, 9, 256, 81, 16, 25, 6, 7, 8, 9, 10, 256, 81, 16, 25, 6, 7, 8, 9, 10, 11, 1024, 243, 64, 25, 36, 7, 8, 9, 10, 11, 12
(list; table; graph; refs; listen; history; internal format)
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OFFSET
| 2,1
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COMMENTS
| Row sums are:
{2, 5, 15, 20, 40, 47, 179, 260, 418, 429, 1449,...}. I use:
t(n,m)=m^Sum[Floor[n/m^k], {k, 1, 12}];
for the sake of time ( answer is the same at lower powers).
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FORMULA
| t(n,m)=m^Sum[Floor[n/m^k], {k, 1, Infinity}].
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EXAMPLE
| {2},
{2, 3},
{8, 3, 4},
{8, 3, 4, 5},
{16, 9, 4, 5, 6},
{16, 9, 4, 5, 6, 7},
{128, 9, 16, 5, 6, 7, 8},
{128, 81, 16, 5, 6, 7, 8, 9},
{256, 81, 16, 25, 6, 7, 8, 9, 10},
{256, 81, 16, 25, 6, 7, 8, 9, 10, 11},
{1024, 243, 64, 25, 36, 7, 8, 9, 10, 11, 12}
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MATHEMATICA
| Table[Table[m^Sum[Floor[n/m^k], {k, 1, 12}], {m, 2, n}], {n, 2, 12}]
Flatten[%]
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CROSSREFS
| Sequence in context: A139073 A099870 A110985 * A141611 A145596 A135835
Adjacent sequences: A153213 A153214 A153215 * A153217 A153218 A153219
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KEYWORD
| nonn,tabl
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AUTHOR
| Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Dec 20 2008
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