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A152892
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Periodic sequence [0,3,1,0,1] of period 5
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2
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0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1, 0, 3, 1, 0, 1
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OFFSET
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0,2
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LINKS
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Table of n, a(n) for n=0..104.
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FORMULA
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a(n+5) = a(n) with a(0) = a(3) = 0, a(1) = 3 and a(2) = a(4) = 1 ; o.g.f f(z) = ((3*z+z^2+z^4)/(1-z^5)) ;
a(n) = 1+(-1/2+3/10*5^(1/2))*cos(2*n*Pi/5)+(1/5*2^(1/2)*(5+5^(1/2))^(1/2)+1/10*2^(1/2)*(5-5^(1/2))^(1/2))*sin(2*n*Pi/5)+(-1/2-3/10*5^(1/2))*cos(4*n*Pi/5)+(-1/10*2^(1/2)*(5+5^(1/2))^(1/2)+1/5*2^(1/2)*(5-5^(1/2))^(1/2))*sin(4*n*Pi/5)
a(n)=(1/10)*{3*(n mod 5)-[(n+1) mod 5]+3*[(n+2) mod 5]+5*[(n+3) mod 5]-5*[(n+4) mod 5]}, with n>=0 [From Paolo P. Lava, Dec 15 2008]
a(n) = (n^3+2*n^2)mod 5 [From Gary Detlefs, Mar 20 2010]
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MAPLE
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seq((n^3+2*n^2)mod 5, n=0..50); [From Gary Detlefs, Mar 20 2010]
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CROSSREFS
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026053, A026068
Sequence in context: A120080 A111700 A060096 * A193002 A181116 A051834
Adjacent sequences: A152889 A152890 A152891 * A152893 A152894 A152895
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KEYWORD
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easy,nonn
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AUTHOR
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Richard Choulet, Dec 14 2008
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STATUS
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approved
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