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A152841
a(0)=1; a(n)=Floor[n^(n+a(n-1))-a(n-1)^(n+a(n-1))].
0
1, 0, -4, -1, -115, -1
OFFSET
0,3
MATHEMATICA
lst={}; a=1; Do[a=a^(n+a)-n^(n+a); AppendTo[lst, Floor[a]], {n, 0, 5}]; lst
KEYWORD
sign
AUTHOR
EXTENSIONS
Indices added to definition, offset corrected - R. J. Mathar, Jan 08 2009
STATUS
approved