|
|
A152767
|
|
3 times 10-gonal (or decagonal) numbers: 3n(4n-3).
|
|
12
|
|
|
0, 3, 30, 81, 156, 255, 378, 525, 696, 891, 1110, 1353, 1620, 1911, 2226, 2565, 2928, 3315, 3726, 4161, 4620, 5103, 5610, 6141, 6696, 7275, 7878, 8505, 9156, 9831, 10530, 11253, 12000, 12771, 13566, 14385, 15228, 16095, 16986
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,2
|
|
COMMENTS
|
|
|
REFERENCES
|
"Supplemento al Periodico di Matematica", Raffaello Giusti Editore (Livorno), Jan. 1910 p. 47 (Problem 1052).
|
|
LINKS
|
|
|
FORMULA
|
a(n) = 12*n^2 - 9*n = 3*A001107(n).
a(n) = sum(A001539(k), k=0..n-1)-sum(4*A002939(k), k=0..n-1) if n>0 (see References, Problem 1052). - Bruno Berselli, Dec 08 2010 - Jan 21 2011
G.f.: -3*x*(1+7*x)/(x-1)^3.
a(0)=0, a(1)=3, a(2)=30, a(n)=3*a(n-1)-3*a(n-2)+a(n-3). - Harvey P. Dale, May 26 2012
|
|
EXAMPLE
|
For n=8, a(8)=(1*3+5*7+9*11+..+29*31)-(2*4+6*8+10*12+..+26*28) = 696 (see Problem 1052 in References). - Bruno Berselli, Dec 12 2010
|
|
MATHEMATICA
|
Table[3n(4n-3), {n, 0, 40}] (* or *) LinearRecurrence[{3, -3, 1}, {0, 3, 30}, 40] (* Harvey P. Dale, May 26 2012 *)
|
|
PROG
|
|
|
CROSSREFS
|
Cf. numbers of the form n*(n*k-k+6))/2, this sequence is the case k=24: see Comments lines of A226492.
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|