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A152586
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Numbers of the form 13^(2^n) + 2.
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0
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OFFSET
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1,1
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COMMENTS
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These numbers are divisible by 3. Expanding the binomial (12+1)^(2^n)+1 we
get 12h+1+2 for some h and 12h+3 is divisible by 3.
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LINKS
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FORMULA
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PROG
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(PARI) g(a, n) = if(a%2, b=2, b=1); for(x=0, n, y=a^(2^x)+b; print1(y", "))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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