

A152204


Triangle read by rows: T(n,k) = 2*n4*k+5 (n >= 0, 1 <= k <= 1+floor(n/2)).


6



1, 3, 5, 1, 7, 3, 9, 5, 1, 11, 7, 3, 13, 9, 5, 1, 15, 11, 7, 3, 17, 13, 9, 5, 1, 19, 15, 11, 7, 3, 21, 17, 13, 9, 5, 1, 23, 19, 15, 11, 7, 3, 25, 21, 17, 13, 9, 5, 1, 27, 23, 19, 15, 11, 7, 3, 29, 25, 21, 17, 13, 9, 5, 1, 31, 27, 23, 19, 15, 11, 7, 3, 33
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

0,2


COMMENTS

All terms are odd, decreasing across rows. Row sums = A000217, the triangular numbers.
From Johannes W. Meijer, Sep 08 2013: (Start)
Triangle read by rows formed from the antidiagonals of triangle A099375.
The alternating row sums equal A098181(n). (End)


LINKS

Nathaniel Johnston, Rows n = 0..200 of irregular triangle, flattened


FORMULA

By columns, odd terms in every column, nth column starts at row (2*n).
From Johannes W. Meijer, Sep 08 2013: (Start)
T(n, k) = A099375(nk+1, k1), n >= 0 and 1 <= k <= 1+floor(n/2)).
T(n, k) = A158405(n+1, n2*k+2). (End)


EXAMPLE

First few rows of the triangle =
1
3
5 1
7 3
9 5 1
11 7 3
13 9 5 1
15 11 7 3
17 13 9 5 1
19 15 11 7 3
21 17 13 9 5 1
...


MAPLE

T := proc(n, k) return 2*n4*k+5: end: seq(seq(T(n, k), k=1..1+floor(n/2)), n=0..20); # Nathaniel Johnston, May 01 2011


CROSSREFS

Cf. A000217.
Sequence in context: A320051 A158858 A202356 * A114216 A208509 A086233
Adjacent sequences: A152201 A152202 A152203 * A152205 A152206 A152207


KEYWORD

nonn,tabf,easy


AUTHOR

Gary W. Adamson, Nov 29 2008


EXTENSIONS

Edited by N. J. A. Sloane, Sep 25 2010, following a suggestion from Emeric Deutsch
Offset corrected by Johannes W. Meijer, Sep 07 2013


STATUS

approved



