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A152196 A sequence based on the digits of Log(10) as a BBP: a(k)=Floor[Mod[(1/2)*((-4)^k)*(6/(4*k + 1) - 3/(4*k + 3) - 1/(4*k + 4)), 3]]. 1

%I #9 Feb 25 2017 18:29:55

%S 2,1,2,2,0,1,1,1,0,0,1,0,1,1,0,0,1,1,0,0,0,2,0,1,1,1,2,2,0,2,2,1,0,0,

%T 2,0,2,0,2,0,1,0,2,2,1,1,1,0,0,2,1,0,1,0,1,0,0,1,2,0,0,0,2,2,1,0,1,0,

%U 2,2,2,0,2,1,0,2,2,0,0,1,1,2,2,2,1,0,2,1,2,1,2,0,0,1,1,0,0,2,2,2,2

%N A sequence based on the digits of Log(10) as a BBP: a(k)=Floor[Mod[(1/2)*((-4)^k)*(6/(4*k + 1) - 3/(4*k + 3) - 1/(4*k + 4)), 3]].

%H G. C. Greubel, <a href="/A152196/b152196.txt">Table of n, a(n) for n = 0..1000</a>

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/BBP-TypeFormula.html">BBP-Type Formula</a>

%F a(k) = Floor[Mod[(1/2)*((-4)^k)*(6/(4*k + 1) - 3/(4*k + 3) - 1/(4*k + 4)), 3]].

%t Table[Floor[Mod[(1/2)*((-4)^k)*(6/(4*k + 1) - 3/(4*k + 3) - 1/(4*k + 4)), 3]], {k, 0, 100}]

%K nonn,base

%O 0,1

%A _Roger L. Bagula_ and _Alexander R. Povolotsky_, Nov 28 2008

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Last modified April 24 20:08 EDT 2024. Contains 371963 sequences. (Running on oeis4.)