OFFSET
1,1
COMMENTS
Primes p dividing 10^(2*d)+10^d+1 where d=ceiling(log(p)/log(10)) is the number of decimal digits in p. - Max Alekseyev
There is no prime p such that p^2 divides p.p.
All primes of the forms 10^(2m) - 10^m + 1 or (1/3)*(10^(2m) + 10^m + 1) are in the sequence.
Primes in A243162. - Hans Havermann, May 31 2014
a(11) > 10^158. - Max Alekseyev, Sep 11 2024
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
Farideh Firoozbakht, Dec 26 2008
STATUS
approved