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A146898
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Lower polynomial approximation of Eulerian numbers: t0(n,m)=If[Mod[2*Binomial[n, m], 2] - Mod[Binomial[n, m], 2] == 0, Binomial[n, m]/2, Binomial[n, m] + 1]; p(x,n)=If[n == 0, 1, (x + 1)^n + Sum[t0(n,m)*x^m*(1 + x^(n - 2*m)), {m, 1, n - 1}]].
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0
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1, 1, 1, 1, 4, 1, 1, 11, 11, 1, 1, 8, 12, 8, 1, 1, 17, 20, 20, 17, 1, 1, 12, 47, 40, 47, 12, 1, 1, 23, 65, 107, 107, 65, 23, 1, 1, 16, 56, 112, 140, 112, 56, 16, 1, 1, 29, 72, 168, 252, 252, 168, 72, 29, 1, 1, 20, 137, 240, 420, 504, 420, 240, 137, 20, 1
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OFFSET
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0,5
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COMMENTS
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Row sums are:{1, 2, 6, 24, 30, 76, 160, 392, 510, 1044, 2140}. The effort here was to match the modulo two behavior to the Sierpinski gasket while adding a term polynomial.
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LINKS
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FORMULA
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t0(n,m)=If[Mod[2*Binomial[n, m], 2] - Mod[Binomial[n, m], 2] == 0, Binomial[n, m]/2, Binomial[n, m] + 1]; p(x,n)=If[n == 0, 1, (x + 1)^n + Sum[t0(n,m)*x^m*(1 + x^(n - 2*m)), {m, 1, n - 1}]]; t(n,m)=coefficients(p(x,n)).
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EXAMPLE
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{1}, {1, 1}, {1, 4, 1}, {1, 11, 11, 1}, {1, 8, 12, 8, 1}, {1, 17, 20, 20, 17, 1}, {1, 12, 47, 40, 47, 12, 1}, {1, 23, 65, 107, 107, 65, 23, 1}, {1, 16, 56, 112, 140, 112, 56, 16, 1}, {1, 29, 72, 168, 252, 252, 168, 72, 29, 1}, {1, 20, 137, 240, 420, 504, 420, 240, 137, 20, 1}
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MATHEMATICA
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Clear[t, p, x, n]; t[n_, m_] = If[Mod[2*Binomial[n, m], 2] - Mod[Binomial[n, m], 2] == 0, Binomial[n, m]/2, Binomial[n, m] + 1]; p[x_, n_] = If[n == 0, 1, (x + 1)^n + Sum[t[n, m]*x^m*(1 + x^(n - 2*m)), {m, 1, n - 1}]]; Table[CoefficientList[FullSimplify[ExpandAll[p[x, n]]], x], {n, 0, 10}]; Flatten[%]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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