|
| |
|
|
A146569
|
|
Numbers m with the property that shifting the rightmost digit of m to the left end multiplies the number by 4.
|
|
1
| |
|
|
102564, 128205, 153846, 179487, 205128, 230769, 102564102564, 128205128205, 153846153846, 179487179487, 205128205128, 230769230769, 102564102564102564, 128205128205128205, 153846153846153846, 179487179487179487
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,1
|
|
|
COMMENTS
| a(13) <= 102564102564102564. [From Donovan Johnson (donovan.johnson(AT)yahoo.com), Jun 06 2009]
The condition is equivalent to the numbers being of the form 10*m+d with a k-digit number m and a non-zero digit d such that 4*(10*m+d) = 10^k * d + m, i.e. 39*m = (10^k - 4)*d. Checking modulo 13, this implies k = 5 (mod 6). Also, m >= 10^(k-1) implies d >= 4. Each such k and d leads to a solution. [From Hagen von Eitzen (math(AT)von-eitzen.de), Jun 26 2009]
|
|
|
FORMULA
| If n = 6*k + r with 1 <= r <=6, then a(n) = (10^(6*k)-1)/(10^6-1) * a(r) as well as a(n) = floor( (r+3)/39 * 10^(6*(k+1)) ) [From Hagen von Eitzen (math(AT)von-eitzen.de), Jun 26 2009]
|
|
|
PROG
| (PARI) a(n) = local(r=(n-1)%6+1, k=(n-r)/6); floor((r+3)/39*10^(6*(k+1))) [From Hagen von Eitzen (math(AT)von-eitzen.de), Jun 26 2009]
|
|
|
CROSSREFS
| Cf. A146088.
Sequence in context: A010329 A184567 A034089 * A081463 A014884 A015330
Adjacent sequences: A146566 A146567 A146568 * A146570 A146571 A146572
|
|
|
KEYWORD
| nonn,base
|
|
|
AUTHOR
| N. J. A. Sloane, based on correspondence from William A. Hoffman III (whoff(AT)robill.com), Apr 10 2009
|
|
|
EXTENSIONS
| a(7)-a(12) from Donovan Johnson (donovan.johnson(AT)yahoo.com), Jun 06 2009
More terms from Hagen von Eitzen (math(AT)von-eitzen.de), Jun 26 2009
|
| |
|
|