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A146360 Primes p such that continued fraction of (1 + sqrt(p))/2 has period 15: primes in A146338. 37
193, 281, 1861, 1933, 2089, 2141, 2437, 2741, 2837, 3037, 3121, 3413, 4001, 4637, 4877, 5821, 6653, 7673, 8117, 10069, 10273, 10457, 11197, 11549, 11821, 12409, 13037, 14653, 15061, 15077, 18661, 20549, 22921, 23117, 24169, 25621, 28837, 35597, 35869, 36389, 38569 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
LINKS
MAPLE
A146326 := proc(n) if not issqr(n) then numtheory[cfrac]( (1+sqrt(n))/2, 'periodic', 'quotients') ; nops(%[2]) ; else 0 ; fi; end: isA146360 := proc(n) RETURN(isprime(n) and A146326(n) = 15) ; end: for n from 2 to 30000 do if isA146360(n) then printf("%d, \n", n) ; fi; od: # R. J. Mathar, Sep 06 2009
MATHEMATICA
Select[Prime[Range[1500]], Length[ContinuedFraction[(Sqrt[#]+1)/2][[2]]] == 15&] (* Harvey P. Dale, Aug 16 2014 *)
CROSSREFS
Sequence in context: A020352 A146338 A201858 * A050964 A015988 A260539
KEYWORD
nonn
AUTHOR
Artur Jasinski, Oct 30 2008
EXTENSIONS
8539 removed by R. J. Mathar, Sep 06 2009
More terms from Amiram Eldar, Mar 30 2020
STATUS
approved

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Last modified March 29 02:23 EDT 2024. Contains 371264 sequences. (Running on oeis4.)