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A146355
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Primes p such that continued fraction of (1+Sqrt[p])/2 has period 10 : primes in A146335.
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1
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43, 67, 563, 827, 1787, 1811, 2099, 2459, 5107, 7643, 8363, 9323, 9371, 9467
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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MATHEMATICA
| $MaxExtraPrecision = 4000; s = 10; aa = {}; Do[k = ContinuedFraction[(1 + Sqrt[Prime[n]])/2, 3000]; m = 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]], m++ ]; s = s + 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]], m++ ]; s = s + 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]]; AppendTo[aa, m]], {n, 1, 1495}]; bb = {}; Do[If[aa[[n]] == 10, AppendTo[bb, Prime[n]]], {n, 1, Length[aa]}]; bb (*Artur Jasinski*)
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CROSSREFS
| A000290, A050950-A050969, A078370, A146326-A146345, A146348-A146360.
Sequence in context: A033229 A139875 A174812 * A175730 A087765 A141971
Adjacent sequences: A146352 A146353 A146354 * A146356 A146357 A146358
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KEYWORD
| nonn
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AUTHOR
| Artur Jasinski (grafix(AT)csl.pl), Oct 30 2008
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