OFFSET
1,2
COMMENTS
Looking on the number of 1`s, 2`s,...k`s in this sequence we obtain the sequence (1,2,4,5,9,16,25,42,72,...). Lim_k-->oo [number of (k+1)`s / number of(k`s)] = sqrt(e).
MATHEMATICA
IntegerPart[Accumulate[1/EulerPhi[Range[110]]]] (* Harvey P. Dale, Dec 19 2015 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Ctibor O. Zizka, Oct 30 2008
STATUS
approved