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A146079 Period 9: repeat 2,4,8,5,4,5,8,4,2. 2
2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5, 8, 4, 2, 2, 4, 8, 5, 4, 5 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,1

COMMENTS

Also the decimal expansion of 82848614/333333333 or the continued fraction rep. of (252629+sqrt(142904412730))/281217.

Palindromic symmetry: a(9k+i) = a(9k+8-i).

LINKS

Table of n, a(n) for n=0..104.

FORMULA

a(n)=a(n-9).

G.f.: -(2+4*x+8*x^2+5*x^3+4*x^4+5*x^5+8*x^6+4*x^7+2*x^8) / ((x-1) * (1+x+x^2) * (x^6+x^3+1)) .

a(n)=(1/54)*{7*(n mod 9)+19*[(n+1) mod 9]+31*[(n+2) mod 9]-11*[(n+3) mod 9]+[(n+4) mod 9]+13*[(n+5) mod 9]+25*[(n+6) mod 9]-17*[(n+7) mod 9]-5*[(n+8) mod 9]}, with n>=0 [From Paolo P. Lava, Sep 16 2009]

a(n) = n^2 + n + 2 (mod 9). [Arkadiusz Wesolowski, Jul 03 2012]

MATHEMATICA

Flatten@Table[{2, 4, 8, 5, 4, 5, 8, 4, 2}, {10}] (* Arkadiusz Wesolowski, Jul 03 2012 *)

CROSSREFS

Sequence in context: A135447 A163339 A092892 * A165669 A021893 A036117

Adjacent sequences:  A146076 A146077 A146078 * A146080 A146081 A146082

KEYWORD

nonn,easy

AUTHOR

Paul Curtz, Oct 27 2008

EXTENSIONS

Unrelated comments removed by R. J. Mathar, Sep 07 2009

STATUS

approved

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Last modified May 24 09:26 EDT 2013. Contains 225617 sequences.