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A145995
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a(n) = 8 - 12*n + 5*n^2.
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3
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1, 4, 17, 40, 73, 116, 169, 232, 305, 388, 481, 584, 697, 820, 953, 1096, 1249, 1412, 1585, 1768, 1961, 2164, 2377, 2600, 2833, 3076, 3329, 3592, 3865, 4148, 4441, 4744, 5057, 5380, 5713, 6056, 6409, 6772, 7145, 7528, 7921, 8324, 8737, 9160, 9593, 10036
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OFFSET
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1,2
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COMMENTS
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For n > 1, a(n) is square if and only if n-1 is in A081016.
a(n) and a(-n) give all numbers m such that 5*m-4 is a square. - Bruno Berselli, Feb 03 2016
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LINKS
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FORMULA
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a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n>3, a(1)=1, a(2)=4, a(3)=17.
G.f.: x*(1 + x + 8*x^2)/(1-x)^3.
E.g.f.: (5*x^2 - 7*x + 8)*exp(x) - 8. (End)
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EXAMPLE
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MATHEMATICA
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Table[8 -12x +5x^2, {x, 50}]
s = 1; lst = {s}; Do[s += n + 2; AppendTo[lst, s], {n, 1, 450, 10}]; lst (* Zerinvary Lajos, Jul 11 2009 *)
LinearRecurrence[{3, -3, 1}, {1, 4, 17}, 51] (* G. C. Greubel, Jan 30 2016 *)
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PROG
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(PARI) for(n=1, 50, print1(8-12*n+5*n^2, ", ")) \\ Klaus Brockhaus, Oct 29 2008
(Magma) [8-12*n+5*n^2: n in [1..50]]; // G. C. Greubel, Jul 15 2019
(Sage) [8-12*n+5*n^2 for n in (1..50)] # G. C. Greubel, Jul 15 2019
(GAP) List([1..50], n-> 8-12*n+5*n^2); # G. C. Greubel, Jul 15 2019
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CROSSREFS
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Cf. A195162 (numbers m such that 5*m+4 is a square).
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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Corrected definition; corrected comment; added keyword. - Klaus Brockhaus, Oct 29 2008
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STATUS
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approved
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