|
| |
|
|
A145652
|
|
a(1)=1. a(n) = the largest integer such that the finite sequence (a(n-1),a(n-2),...a(n-a(n))) occurs somewhere as a subsequence in the finite sequence (a(1),a(2),...,a(n-1)).
|
|
1
| |
|
|
1, 1, 2, 1, 3, 1, 3, 3, 2, 1, 2, 3, 5, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 4, 1, 1, 2, 2, 2, 3, 2, 3
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,3
|
|
|
COMMENTS
| a(n+12) = a(n) for all n >= 14.
|
|
|
LINKS
| "Hagman", Sci Math Thread
|
|
|
EXAMPLE
| The subsequence of terms a(27) through a(29) in reversed order is (a(29),a(28),a(27)) = (3,3,2). This occurs in the first 29 terms of sequence A145652 like so: 1,1,2,1,3,1,(3,3,2),1,2,3,5,1,1,2,2,2,3,2,2,5,1,1,2,2,2,3,3. On the other hand, the subsequence of terms a(26) to a(29) in reversed order, (3,3,2,2) does not occur anywhere among the first 29 terms of sequence A145652. Since there are three terms in (3,3,2), then a(30) = 3.
|
|
|
CROSSREFS
| Sequence in context: A039776 A048864 A003139 * A111248 A100714 A050123
Adjacent sequences: A145649 A145650 A145651 * A145653 A145654 A145655
|
|
|
KEYWORD
| nonn
|
|
|
AUTHOR
| Leroy Quet Oct 15 2008, corrected Oct 20 2008
|
| |
|
|
