1,1
General formula for a(n+1)=a(n)^2+2*a(n)-2 and a(1)=k+1 is a(n)=Floor[((k + Sqrt[k^2 + 4])/2)^(2^((n+1) - 1))
aa = {}; k = 7; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa
or
k =6; Table[Floor[((k + Sqrt[k^2 + 4])/2)^(2^(n - 1))], {n, 2, 7}] (*Artur Jasinski*)
A145502-A145511
Sequence in context: A049402 A001830 A048287 * A047685 A171078 A180776
Adjacent sequences: A145504 A145505 A145506 * A145508 A145509 A145510
nonn
Artur Jasinski (grafix(AT)csl.pl), Oct 11 2008
