1,1
General formula for a(n+1)=a(n)^2+2*a(n)-2 and a(1)=k+1 is a(n)=Floor[((k + Sqrt[k^2 + 4])/2)^(2^((n+1) - 1))
aa = {}; k = 2; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa
or
k = 1; Table[Floor[((k + Sqrt[k^2 + 4])/2)^(2^(n - 1))], {n, 2, 7}] (*Artur Jasinski*)
A145502-A145511
Sequence in context: A078603 A001587 A078537 * A072444 A052596 A098710
Adjacent sequences: A145499 A145500 A145501 * A145503 A145504 A145505
nonn
Artur Jasinski (grafix(AT)csl.pl), Oct 11 2008
