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A145384
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The number of terms of A050791 bracketed by successive terms of A141326
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2
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0, 1, 2, 3, 2, 3, 2, 2, 6, 6, 0, 3, 1, 3, 2, 3, 2, 4, 4, 3, 0, 3, 5, 0, 2, 2, 3, 2, 1, 2, 3, 1, 2, 3, 5, 1, 1, 4, 2, 0, 1, 3, 1, 3, 3, 2, 2, 2, 4, 2, 1, 2, 4, 2, 0, 1, 2, 3, 1, 1, 1, 3, 0, 3, 1, 0, 3, 1, 1, 4, 2, 2, 1, 3, 3, 1, 2, 0, 3, 2, 5, 1, 1, 3, 6, 2, 4, 1, 0, 5, 2, 2, 2, 2, 3, 2, 3, 3, 0, 1
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OFFSET
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1,3
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COMMENTS
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A141326 is a simply generated subsequence of A050791 and by observation it forms a natural measure of the parent sequence. The first several hundred terms of the parent sequence not belonging to A141326 are bracketed into groups with a small integral number of terms ( including 0 ) by the successive terms of the subsequence, A141326.
a(107),a(108) are the first occurrence of 2 consecutive 0's and a(119),a(120),a(121) are the first occurrence of 3 consecutive 0's. This leads to the following conjecture:
<a(n)> -> 0 as n ->inf
where <a(n)> = ( sum m=1,n of a(m) )/n
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LINKS
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Lewis Mammel, Table of n, a(n) for n = 1..122
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FORMULA
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a(1) = A145383(1) - 1
a(n) = A145383(n) - A145383(n-1) - 1 ; n>1
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EXAMPLE
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0 = number of terms of A050791 preceding the first term of A141326
1 = number of terms of A050791 between the first and 2nd terms of A141326
2 = number of terms of A050791 between the 2nd and 3rd terms of A141326
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CROSSREFS
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Cf. A145383, A141326, A050791
Sequence in context: A175066 A066102 A036048 * A117666 A165587 A010693
Adjacent sequences: A145381 A145382 A145383 * A145385 A145386 A145387
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KEYWORD
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nonn
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AUTHOR
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Lewis Mammel (l_mammel(AT)att.net), Oct 10 2008
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STATUS
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approved
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