1,1
Table of n, a(n) for n=1..8.
a(n+2)=33710*a(n+1)-a(n)
a(n)=(7/2)*{[16855+1484*sqrt(129)]^n+[16855-1484*sqrt(129)]^n}-(53/172)*sqrt(129)*{[16855-1484*sqrt(129)]^n- [16855+1484*sqrt(129)]^n}, with n>=0 [From Paolo P. Lava, Nov 25 2008]
a(1)=7 because the first relation is : 27^3-26^3=43*7^2
Sequence in context: A090769 A013842 A145322 * A003835 A138878 A050938
Adjacent sequences: A145332 A145333 A145334 * A145336 A145337 A145338
easy,nonn
Richard Choulet, Oct 08 2008
approved