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A145322 Numbers n such that there exists x in N : (x+1)^3-x^3=31*n^2. 1

%I #17 Jan 17 2024 09:56:47

%S 7,170107,4133940307,100463017170607,2441452239146151007,

%T 59332172215266744601507,1441890446733960188159672107,

%U 35040821577196528277389606942807,851562044527139583463162039764423607,20694660771057724580125235612965415554507

%N Numbers n such that there exists x in N : (x+1)^3-x^3=31*n^2.

%H Michael De Vlieger, <a href="/A145322/b145322.txt">Table of n, a(n) for n = 1..228</a>

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (24302,-1).

%F a(n+2) = 24302*a(n+1)-a(n).

%F G.f.: -7*x*(x-1) / (x^2-24302*x+1). - _Colin Barker_, Oct 19 2014

%e a(1)=7 because 23^3-22^3=31*7^2.

%t LinearRecurrence[{24302, -1}, {7, 170107}, 10] (* _Paolo Xausa_, Jan 17 2024 *)

%o (PARI) Vec(-7*x*(x-1)/(x^2-24302*x+1) + O(x^20)) \\ _Colin Barker_, Oct 19 2014

%K easy,nonn

%O 1,1

%A _Richard Choulet_, Oct 07 2008

%E Editing and a(10) from _Colin Barker_, Oct 19 2014

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Last modified April 19 03:57 EDT 2024. Contains 371782 sequences. (Running on oeis4.)