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A145294 Smallest x >= 0 such that the Euler polynomial x^2 + x + 41 has a prime divisor of multiplicity n. 7

%I #35 Jan 23 2019 16:18:56

%S 0,40,1721,14144,2294005,326924482,6386359423,1341160319494,

%T 149759650255065,1167478867440605,243422399538851918,

%U 9662500171353620019,122479951673184550424,12148820281768361731597,177497315692809432279207,11767210525408975519141638

%N Smallest x >= 0 such that the Euler polynomial x^2 + x + 41 has a prime divisor of multiplicity n.

%C The Euler polynomial gives primes for consecutive x from 0 to 39.

%C For numbers x for which x^2 + x + 41 is not prime, see A007634.

%C For composite numbers of the form x^2 + x + 41, see A145292.

%C For the smallest x such that polynomial x^2 + x + 41 has exactly n distinct prime divisors, see A145293.

%C Sequence interpreted as a(n)^2 + a(n) + 41 having a prime divisor with multiplicity that is exactly n. - _Bert Dobbelaere_, Jan 22 2019

%H Bert Dobbelaere, <a href="/A145294/b145294.txt">Table of n, a(n) for n = 1..100</a>

%H Bert Dobbelaere, <a href="/A145294/a145294_1.py.txt">Python program</a>

%e a(2)=40 because when x=40 then x^2 + x + 41 = 1681 = 41^2;

%e a(3)=1721 because when x=1721 then x^2 + x + 41 = 2963603 = 43*41^3;

%e a(4)=14144 because when x=14144 then x^2 + x + 41 = 200066921 = 41*47^4;

%e a(5)=2294005 because when x=2294005 then x^2 + x + 41 = 5262461234071 = 35797*43^5.

%e a(6)=326924482: a(6)^2 + a(6) + 41 = 106879617257892847 = 9915343 * 47^6. - _Hugo Pfoertner_, Mar 08 2018

%Y Cf. A005846, A007634, A145292, A145293, A145295.

%K nonn

%O 1,2

%A _Artur Jasinski_, Oct 07 2008

%E Title changed, a(1) and a(6) from _Hugo Pfoertner_, Mar 08 2018

%E More terms from _Bert Dobbelaere_, Jan 22 2019

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Last modified April 25 11:39 EDT 2024. Contains 371969 sequences. (Running on oeis4.)