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A145271 Coefficients for expansion of [g(x)d/dx]^n g(x); refined Eulerian numbers for calculating compositional inverse of h(x)= (d/dx)^(-1) 1/g(x). 18
1, 1, 1, 1, 1, 4, 1, 1, 11, 4, 7, 1, 1, 26, 34, 32, 15, 11, 1 (list; graph; refs; listen; history; internal format)
OFFSET

0,6

COMMENTS

For more detail, including connections to Legendre transformations, rooted trees, A139605, A139002 and A074060, see Copeland link pg. 9.

For connections to the h-polynomials associated to the refined f-polynomials of permutohedra see my comments in A008292 and A049019.

Contribution by Tom Copeland Oct 14 2011: (Start)

Given analytic functions F(x) and FI(x) such that F(FI(x))=FI(F(x))=x about 0, i.e., they are compositional inverses of each other, then, with g(x)= 1/dFI(x)/dx, a flow function W(s,x) can be defined with the following relations:

W(s,x)= exp[s g(x)d/dx]x = F[s+FI(x)] <flow fct.>,

W(s,0)= F(s), <orbit of the flow>,

W(0,x)= x  <identity property>,

dW(0,x)/ds = g(x) = F'[FI(x)], <differentiability prop.>, implying

dW(0,F(x))/ds = g(F(x)) = F'[x], <autonomous diff. eqn.>, and

W[s,W(r,x)] = F{s+FI[F[r+FI(x)]]} = F[s+r+FI(x)] = W(s+r,x) <group property>. (See MF link below.)(End)

dW(s,x)/ds - g(x)dW(s,x)/dx = 0, so (1,-g(x)) are the components of a vector orthogonal to the gradient of W and, therefore, tangent to the contour of W, at (s,x). - Tom Copeland. Oct 26 2011

Though A139605 contains A145271, the op. of A145271 contains that of A139605 in the sense that exp[s g(x)d/dx] w(x)= w{F[s+FI(x)]}

  = exp{[exp(s g(x)d/dx)x]d/du}w(u) eval. at u=0. This is reflected in the fact that the forest of rooted trees assoc. to (g(x)d/dx)^n, FOR_n, can be generated by removing the single trunk of the planted rooted trees of FOR_(n+1). - Tom Copeland, Nov 29 2011

LINKS

M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 .

Tom Copeland, Flipping Functions with Permutohedra Posted Oct. 2008 [From Tom Copeland (tcjpn(AT)msn.com), Oct 08 2008]

Tom Copeland, Mathemagical Forests v2 Posted June 2008

T. Copeland, Addendum to Mathemagical Forests

EXAMPLE

Let R = g(x)d/dx then

R^0 g(x) = 1 (0')^1

R^1 g(x) = 1 (0')^1 (1')^1

R^2 g(x) = 1 (0')^1 (1')^2 + 1 (0')^2 (2')^1

R^3 g(x) = 1 (0')^1 (1')^3 + 4 (0')^2 (1')^1 (2')^1 + 1 (0')^3 (3')^1

R^4 g(x) = 1 (0')^1 (1')^4 + 11 (0')^2 (1')^2 (2')^1 + 4 (0')^3 (2')^2 + 7 (0')^3 (1')^1 (3')^1 + 1 (0')^4 (4')^1

where (j')^k = [(d/dx)^j g(x)]^k . And R^(n-1) g(x) evaluated at x=0 is the n-th Taylor series coefficient of the compositional inverse of h(x)= (d/dx)^(-1) 1/g(x), with the integral from 0 to x.

The partitions are in reverse order to those in Abramowitz and Stegun pg. 831. Summing over coefficients with like powers of (0') gives A008292.

CROSSREFS

Cf. (A133437,A086810,A181289) = (LIF,reduced LIF,associated g(x)), where LIF is a Lagrange inversion formula.

Cf. (A134264,A001263,A119900), (A134685,A134991,A019538), (A133932,A111999,A007318).

Sequence in context: A140711 A164366 A121692 * A203860 A147564 A090981

Adjacent sequences:  A145268 A145269 A145270 * A145272 A145273 A145274

KEYWORD

easy,nonn,tabf

AUTHOR

Tom Copeland (tcjpn(AT)msn.com), Oct 06 2008, Oct 08 2008

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Last modified February 15 14:52 EST 2012. Contains 205822 sequences.