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a(n) = Fibonacci(6^n).
7

%I #30 Dec 04 2022 04:56:05

%S 1,8,14930352,619220451666590135228675387863297874269396512

%N a(n) = Fibonacci(6^n).

%C The next term, a(4), has 271 digits. - _Harvey P. Dale_, Jul 18 2011

%H Seiichi Manyama, <a href="/A145233/b145233.txt">Table of n, a(n) for n = 0..4</a>

%F a(n) = (G^(6^n) - (1 - G)^(6^n))/sqrt(5) where G = (1 + sqrt(5))/2.

%p A145233 := proc(n) combinat[fibonacci](6^n) ; end proc: # _R. J. Mathar_, Apr 01 2011

%t G = (1 + Sqrt[5])/2; Table[Expand[(G^(6^n) - (1 - G)^(6^n))/Sqrt[5]], {n, 1, 6}]

%t (* Second program: *)

%t Fibonacci[6^Range[4]] (* _Harvey P. Dale_, Jul 18 2011 *)

%o (Magma) [Fibonacci(6^n): n in [0..5]]; // _Vincenzo Librandi_, Apr 02 2011

%Y Cf. A000045.

%Y Cf. (k^n)-th Fibonacci number: A058635 (k=2), A045529 (k=3), A145231 (k=4), A145232 (k=5), this sequence (k=6), A145234 (k=7), A250487 (k=8), A250488 (k=9), A250489 (k=10).

%K nonn

%O 0,2

%A _Artur Jasinski_, Oct 05 2008