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 A145210 Numbers n such that there exists x in N : (x+1)^3-x^3=67*n^2 0

%I

%S 31,31935859,32900002583179,33893253661133238151,

%T 34916490989129950608195511,35970619852057890563395800238939,

%U 37056572865356601788515589497544372899

%N Numbers n such that there exists x in N : (x+1)^3-x^3=67*n^2

%F a(n+2)=1030190*a(n+1)-a(n)

%F a(n)=(31/2)*{[515095+124*sqrt(17255649)]^n+[515095-124*sqrt(17255649)]^n}-(1/268)*sqrt(17255649)*{[515095-124 *sqrt(17255649)]^n-[515095+124*sqrt(17255649)]^n}, with n>=0 [From _Paolo P. Lava_, Nov 25 2008]

%e the first relation is : 147^3-146^3=67*31^2

%K easy,nonn

%O 1,1

%A _Richard Choulet_, Oct 04 2008

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Last modified May 23 21:22 EDT 2013. Contains 225611 sequences.