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A145050
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Primes p of the form 4k+1 for which s=26 is the least positive integer such that sp-(floor(sqrt(sp)))^2 is a square.
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5
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OFFSET
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1,1
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COMMENTS
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For all primes of the form 4k+1 not exceeding 10000 the least integer s takes only values: 1, 2, 5, 10, 13, 17, 26. These values are the first numbers in A145017 (see our conjecture at A145047).
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LINKS
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EXAMPLE
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a(1)=6569 since p=6569 is the least prime of the form 4k+1 for which sp-(floor(sqrt(sp)))^2 is not a square for s=1..25, but 26p-(floor(sqrt(26p)))^2 is a square (for p=6569 it is 225).
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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