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%I #2 Mar 30 2012 17:25:32
%S 1,0,1,-1,0,1,-1,-1,0,0,-2,-1,-1,0,-2,-1,-2,-1,0,0,-6,-2,-1,-2,0,2,0,
%T -10,-2,-2,-1,0,2,6,0,-13,-2,-2,-2,0,46,10,0,-10,-1,-2,-2,0,2,12,10,
%U 13,0,4,-2,-1,-2,0,4,6,10,13,10,0,36,-2,-2,-1,0,4,12,10,26,10,-4,0,84,-3
%N Eigentriangle read by rows, T(n,k) = A002321(n-k+1)*A144031(k-1).
%C Row sums = A144031, the INVERT transform of A002321.
%C Left border = the Mertens's function, A002321.
%C Right border = A144031 shifted.
%C Sum of n-th row terms = rightmost term of (n+1)-th row.
%F Eigentriangle read by rows, T(n,k) = A002321(n-k+1)*A144031(k-1).
%e First few rows of the triangle =
%e 1;
%e 0, 1;
%e -1, 0, 1;
%e -1, -1, 0, 0;
%e -2, -1, -1, 0, -2;
%e -1, -2, -1, 0, 0, -6;
%e -2, -1, -2, 0, 2, 0, -10;
%e -2, -2, -1, 0, 2, 6, 0, -13;
%e -2, -2, -2, 0, 4, 6, 10, 0, -10;
%e ...
%e Row 5 = = (-2, -1, -1, 0, -2) termwise products of (-2, -1, -1, 0, 1) and (1, 1, 1, 0, -2); = ((-2)*1, (-1)*(1), (-1)*(1), (0)*(0), (1)*(-2). (-2, -1, -1, 0, 1) = the first 5 terms of A002321, the Mertens's function.
%e (1, 1, 1, 0, -2) = 5 shifted terms of A144031.
%Y A002321, Cf. A144031.
%K tabl,sign
%O 1,11
%A _Gary W. Adamson_, Sep 07 2008
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