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INVERT transform of A002321, Mertens's function.
2

%I #10 Mar 19 2017 01:07:35

%S 1,1,0,-2,-6,-10,-13,-10,4,36,84,137,159,94,-133,-573,-1197,-1788,

%T -1864,-647,2741,8784,16631,22920,20769,87,-49372,-130497,-226511,

%U -286165,-214344,117678,822398,1889427,3022590,3465187,1927286,-3188290,-13016609,-26739085

%N INVERT transform of A002321, Mertens's function.

%C Equals row sums of triangle A144032.

%e Given Mertens's function A002321: (1, 0, -1, -1, -2, ...), apply the INVERT transform.

%e The first 3 terms of A144031 = (1, 1, 1, ...) which we apply to (-1, 0, 1) as a dot product = 0. (-1, 0, 1) = the first 3 terms of A002321 in reverse. [Comment not clear - A144031 can't be right.]

%Y Cf. A002321, A144032.

%K sign

%O 1,4

%A _Gary W. Adamson_, Sep 07 2008

%E More terms from _Alois P. Heinz_, May 23 2015