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Eigentriangle with row sums = A001333 starting (1, 3, 7, 17, 41, 99, ...).
1

%I #5 Feb 08 2022 22:11:26

%S 1,2,1,2,2,3,2,2,6,7,2,2,6,14,17,2,2,6,14,34,41,2,2,6,14,34,82,99,2,2,

%T 6,14,34,82,198,239,2,2,6,14,34,82,198,478,577

%N Eigentriangle with row sums = A001333 starting (1, 3, 7, 17, 41, 99, ...).

%C Right border = A001333.

%C Row sums = shifted A001333: (1, 3, 7, 17, 41, 99, ...) = INVERT transform of (1, 2, 2, 2, ...). Sum of n-th row terms = rightmost term of next row.

%F n-th row of the triangle = n terms of twice A001333: (1, 1, 3, 7, 17, 41, 99, ...) followed by A001333(n).

%e First few rows of the triangle:

%e 1;

%e 2, 1;

%e 2, 2, 3;

%e 2, 2, 6, 7;

%e 2, 2, 6, 14, 17;

%e 2, 2, 6, 14, 34, 41;

%e 2, 2, 6, 14, 34, 82, 99;

%e 2, 2, 6, 14, 34, 82, 198, 239;

%e ...

%Y Cf. A001333.

%K nonn,tabl

%O 0,2

%A _Gary W. Adamson_, Sep 06 2008