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Numbers of the form : k=k^n-n^k, (k=1).
0

%I #2 Mar 31 2012 12:38:16

%S 0,-1,-1,3,118,

%T -199068134034785153195409370979964879499768447341765846329146257207125965412281784631240438087

%N Numbers of the form : k=k^n-n^k, (k=1).

%C The next number is too large to include.

%t lst={};k=1;Do[k=k^n-n^k;AppendTo[lst,IntegerPart[k]],{n,6}];lst

%K sign

%O 1,4

%A _Vladimir Joseph Stephan Orlovsky_, Aug 31 2008