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A143083
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A triangle of coefficients: T(n,m) = (2*n + 2*m + 3)! / (2*(2*m + 1)!*(2*n + 1)!).
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0
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3, 10, 70, 21, 252, 1386, 36, 660, 5148, 25740, 55, 1430, 15015, 97240, 461890, 78, 2730, 37128, 302328, 1763580, 8112468, 105, 4760, 81396, 813960, 5720330, 31201800, 140408100, 136, 7752, 162792, 1961256, 16343800, 104303160, 542911320, 2404321560
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OFFSET
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1,1
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COMMENTS
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Row sums begin: 3, 80, 1659, 31584, 575630, 10218312, 178230451, 3070011776, 52387009722, 887453729920, 14946680628638, ...
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LINKS
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EXAMPLE
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{3},
{10, 70},
{21, 252, 1386},
{36, 660, 5148, 25740},
{55, 1430, 15015, 97240, 461890},
{78, 2730, 37128, 302328, 1763580, 8112468},
{105, 4760, 81396, 813960, 5720330, 31201800, 140408100},
{136, 7752, 162792, 1961256, 16343800, 104303160, 542911320, 2404321560},
{171, 11970, 302841, 4326300, 42181425, 311375610, 1856277675, 9334424880, 40838108850},
{210, 17710, 531300, 8880300, 100150050, 846723150, 5731664400, 32479431600, 159053687100, 689232644100},
{253, 25300, 888030, 17168580, 221760825, 2128903920, 16239715800, 103006197360, 561232295910, 2691289372200, 11572544300460}
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MAPLE
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T := (n, m) -> (n+1)*binomial(2*(n+m+1)+1, 2*m+1):
for n from 0 to 6 do seq(T(n, m), m=0..n) od; # Peter Luschny, Jul 15 2017
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MATHEMATICA
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Table[(2*n + 2*m + 3)!/(2*(2*m + 1)!(2*n + 1)!), {n, 0, 8}, {m, 0, n}] // Flatten
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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