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A142994 Crystal ball sequence for the lattice C_5. 3
1, 51, 501, 2471, 8361, 22363, 50973, 103503, 192593, 334723, 550725, 866295, 1312505, 1926315, 2751085, 3837087, 5242017, 7031507, 9279637, 12069447, 15493449 (list; graph; refs; listen; history; internal format)
OFFSET

0,2

COMMENTS

The lattice C_5 consists of all integer lattice points v = (x_1,...,x_5) in Z^5 such that (x_1 +...+ x_5) is even, equipped with the taxicab type norm ||v|| = 1/2 * (|x_1| +...+ |x_5|). The crystal ball sequence of C_5 gives the number of lattice points v in C_5 with ||v|| <= n for n = 0,1,2,3,... [Bacher et al.].

LINKS

R. Bacher, P. de la Harpe and B. Venkov, Series de croissance et series d'Ehrhart associees aux reseaux de racines, C. R. Acad. Sci. Paris, 325 (Series 1) (1997), 1137-1142.

FORMULA

Partial sums of A019561. a(n) = (2*n+1)*(32*n^4+64*n^3+88*n^2+56*n+15)/15 = sum {k = 0..5} C(10,2k)*C(n+k,5) = sum {k = 0..5} C(10,2k+1)*C(n+k+1/2,5). O.g.f.: (1+45*x+210*x^2+210*x^3+45*x^4+x^5)/(1-x)^6 = 1/(1-x) * T(5,(1+x)/(1-x)), where T(n,x) denotes the Chebyshev polynomial of the first kind. 2*log(2) = 41/30 + sum {n = 1..inf} 1/(n*a(n-1)*a(n)).

EXAMPLE

a(1) = 51. The origin has norm 0. The 50 lattice points in Z^5 of norm 1 (as defined above) are +-2*e_i, 1 <= i <= 5 and (+- e_i +- e_j), 1 <= i < j <= 5, where e_1,...,e_5 denotes the standard basis of Z^5. These 50 vectors form a root system of type C_5. Hence sequence begins 1, 1 + 50 = 51, ... .

MAPLE

a := n -> (2*n+1)*(32*n^4+64*n^3+88*n^2+56*n+15)/15: seq(a(n), n = 0..20)

CROSSREFS

Cf. A019561, A063496, A142992, A142993.

Sequence in context: A204215 A164646 A128511 * A173804 A166820 A020278

Adjacent sequences:  A142991 A142992 A142993 * A142995 A142996 A142997

KEYWORD

easy,nonn

AUTHOR

Peter Bala (pbala(AT)toucansurf.com), Jul 18 2008

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Last modified February 15 09:49 EST 2012. Contains 205763 sequences.