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A141726 Sawtooth with period length 9: repeat 8, 7, 6, 5, 4, 3, 2, 1, 0. 2
8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3, 2, 1, 0, 8, 7, 6, 5, 4, 3 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

Consider the sequence c(n) = c(n+9) = (10*A000027(2*n) + 3*A000027(2*n+1)) mod 9 = (8n+3) mod 9.

Then a(n) = c(n+3).

Also the continued fraction expansion of (23342+5*sqrt(44403565))/6961.

Also the decimal expansion of 973936900/111111111.

LINKS

Table of n, a(n) for n=1..105.

FORMULA

a(n)= a(n-9). G.f.: -x*(8+7*x+6*x^2+5*x^3+4*x^4+3*x^5+2*x^6+x^7)/((x-1)*(1+x+x^2)*(x^6+x^3+1)).

a(n)=(2/9)*{(-7/2)*(n mod 9)+[(n+1) mod 9] + [(n+2) mod 9] + [(n+3) mod 9] + [(n+4) mod 9]+[(n+5) mod 9]+[(n+6) mod 9]+[(n+7) mod 9]+[(n+8) mod 9]}, with n>=0 [From Paolo P. Lava, Sep 29 2008]

CROSSREFS

Cf. A010878.

Sequence in context: A138472 A022964 A023450 * A307339 A031310 A161813

Adjacent sequences:  A141723 A141724 A141725 * A141727 A141728 A141729

KEYWORD

nonn,easy

AUTHOR

Paul Curtz, Sep 13 2008

EXTENSIONS

Index in c-sequence corrected by R. J. Mathar, Sep 11 2009

STATUS

approved

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Last modified January 27 04:57 EST 2020. Contains 331291 sequences. (Running on oeis4.)