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A141681
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Triangle sequence of coefficients: t(n,m)=Inverse[A126988(n,m)*Binomial(n,m)].
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0
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1, -4, 1, -9, 0, 1, 32, -12, 0, 1, -25, 0, 0, 0, 1, 504, -45, -40, 0, 0, 1, -49, 0, 0, 0, 0, 0, 1, -4096, 1568, 0, -140, 0, 0, 0, 1, 2187, 0, -252, 0, 0, 0, 0, 0, 1, 13400, -225, 0, 0, -504, 0, 0, 0, 0, 1
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,2
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COMMENTS
| Row sums are:
{1, -3, -8, 21, -24, 420, -48, -2667, 1936, 12672}.
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FORMULA
| t(n,m)=Inverse[A126988(n,m)*Binomial(n,m)].
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EXAMPLE
| {1},
{-4, 1},
{-9, 0, 1},
{32, -12, 0, 1},
{-25, 0, 0, 0, 1},
{504, -45, -40, 0, 0, 1},
{-49, 0, 0, 0, 0, 0, 1},
{-4096, 1568, 0, -140, 0, 0, 0,1},
{2187, 0, -252, 0, 0, 0, 0,0, 1},
{13400, -225, 0, 0, -504, 0, 0, 0, 0, 1}
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MATHEMATICA
| t[n_, m_] = If[Mod[n, m] == 0, n/m, 0]*Binomial[n, m]; Table[Table[t[n, m], {m, 1, n}], {n, 1, 10}]; Flatten[%]; Table[Sum[t[n, m], {m, 1, n}], {n, 1, 10}]; M = Inverse[Table[Table[t[n, m], {m, 1, 10}], {n, 1, 10}]]; Table[Table[M[[n, m]], {m, 1, n}], {n, 1, 10}]; Flatten[%]
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CROSSREFS
| Cf. A126988.
Sequence in context: A036177 A177841 A141680 * A176215 A143469 A123726
Adjacent sequences: A141678 A141679 A141680 * A141682 A141683 A141684
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KEYWORD
| uned,sign
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AUTHOR
| Roger L. Bagula and Gary W. Adamson (rlbagulatftn(AT)yahoo.com), Sep 07 2008
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