A141519 Period 10: repeat [-1, 1, -3, 7, -5, 3, -7, 9, -9, 5].

-1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3, 7, -5, 3, -7, 9, -9, 5, -1, 1, -3

Offset

0,3

Comments

It appears that abs(a(n)) = abs(A001469(n+1)) mod 10.

It also appears that abs(a(n)) = abs(A228767(n+4)) mod 10. - Michel Marcus, Sep 04 2013

Links

Table of n, a(n) for n=0..92.

Index entries for linear recurrences with constant coefficients, signature (-1,-1,-1,-1,-1,-1,-1,-1,-1).

Formula

G.f.: ( -1-3*x^2+4*x^3+2*x^5-5*x^6-5*x^8-x^4+4*x^7 ) / ( (1+x)*(1+x+x^2+x^3+x^4)*(x^4-x^3+x^2-x+1) ). - R. J. Mathar, Oct 08 2011

a(n) = - Sum_{k=1..9} a(n-k). - Wesley Ivan Hurt, May 27 2021

Mathematica

PadRight[{}, 120, {-1, 1, -3, 7, -5, 3, -7, 9, -9, 5}] (* Harvey P. Dale, Mar 03 2023 *)

Crossrefs

Cf. A001469, A228767.

Sequence in context: A021910 A331632 A094124 * A228000 A029946 A200285

Adjacent sequences: A141516 A141517 A141518 * A141520 A141521 A141522

Keyword

sign,easy,less

Author

Paul Curtz, Aug 11 2008

Status

approved