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A141323 Number of groups of order L(n). 2
1, 1, 1, 2, 1, 1, 5, 1, 1, 4, 1, 1, 4, 2, 1, 9, 1, 1, 30, 1, 1, 11, 5, 1, 4, 1, 2, 9, 2, 1 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,4

COMMENTS

This is to A140987 as Lucas numbers A000032 are to Fibonacci numbers A000045.

LINKS

Table of n, a(n) for n=0..29.

GAP package GrpConst

FORMULA

a(n) = A000001(A000032(n)).

EXAMPLE

a(6) = 5 because the Lucas number L(6) (starting at L(0) = 2) is 18 and there are 5 groups of order 18.

CROSSREFS

Cf. A000001, A000032, A000045, A140987.

Sequence in context: A088347 A069568 A210545 * A210876 A174785 A136789

Adjacent sequences:  A141320 A141321 A141322 * A141324 A141325 A141326

KEYWORD

more,nonn

AUTHOR

Jonathan Vos Post, Aug 02 2008

EXTENSIONS

a(16)-a(29) from Eric M. Schmidt, Jun 20 2014

STATUS

approved

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Last modified June 1 02:09 EDT 2020. Contains 334758 sequences. (Running on oeis4.)