This is to A140987 as Lucas numbers A000032 are to Fibonacci numbers A000045.
Table of n, a(n) for n=0..29.
GAP package GrpConst
a(n) = A000001(A000032(n)).
a(6) = 5 because the Lucas number L(6) (starting at L(0) = 2) is 18 and there are 5 groups of order 18.
Cf. A000001, A000032, A000045, A140987.
Sequence in context: A088347 A069568 A210545 * A210876 A174785 A136789
Adjacent sequences: A141320 A141321 A141322 * A141324 A141325 A141326
Jonathan Vos Post, Aug 02 2008
a(16)-a(29) from Eric M. Schmidt, Jun 20 2014