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A141320
Both n and the smallest number with n divisors are in A002182.
1
1, 2, 4, 6, 12, 24, 36, 48, 60, 120, 180, 240, 360, 720, 1680, 5040, 10080, 20160
OFFSET
1,2
COMMENTS
Question: is this sequence finite? See A189394 for detailed information.
Intersection of A002182 and A002183. - Jianing Song, Apr 03 2018
FORMULA
a(n) = tau(A189394(n)) = A000005(A189394(n)). - Jianing Song, Apr 03 2018
EXAMPLE
Both 20160 and the smallest number with 20160 divisors, 195643523275200, are in A002182, so 20160 is a term.
CROSSREFS
KEYWORD
more,nonn
AUTHOR
J. Lowell, Aug 02 2008
EXTENSIONS
a(16)-a(18) from Jianing Song, Apr 03 2018
STATUS
approved