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%I #12 Sep 21 2019 08:27:51
%S 1,5,3,11,74,93,139,511,641,1166
%N Sequence of k such that starting with P(0)=11 then k(n)*P(n-1)*(k(n)*P(n-1)-1)-1 is the least prime = P(n).
%e 1*11*(1*11-1)-1=109 is a prime so k(1)=1 P(1)=109.
%o (PARI) P=11; for(i=1, 20, k=0; while(!ispseudoprime(t=k++*P*(k*P-1)-1), ); P=t; print1(k", ")) \\ _Michel Marcus_, Sep 16 2019 ; after A141240
%Y Cf. A141233, A141235, A141236, A141237, A141238, A141239, A141240.
%K nonn,more
%O 1,2
%A _Pierre CAMI_, Jun 16 2008
%E a(9) from _Michel Marcus_, Sep 17 2019
%E a(10) from _Jinyuan Wang_, Sep 17 2019
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