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Sum over unitary prime power divisors p^k of n of A025528(p^k).
2

%I #2 Mar 30 2012 17:35:23

%S 0,1,2,3,4,3,5,6,7,5,8,5,9,6,6,10,11,8,12,7,7,9,13,8,14,10,15,8,16,7,

%T 17,18,10,12,9,10,19,13,11,10,20,8,21,11,11,14,22,12,23,15,13,12,24,

%U 16,12,11,14,17,25,9,26,18,12,27,13,11,28,14,15,10,29,13,30,20,16,15,13,12,31

%N Sum over unitary prime power divisors p^k of n of A025528(p^k).

%C Additive with a(p^k) = A025528(p^k).

%F sum_{p^k|n,not p^{k+1}|n,k>0} A025528(p^k).

%Y Cf. A056239, A025528.

%K nonn

%O 1,3

%A _Franklin T. Adams-Watters_, Jun 05 2008